2^(-x)=3x+10

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Solution for 2^(-x)=3x+10 equation: 



2^(-x)=3x+10

We move all terms to the left:

2^(-x)-(3x+10)=0

We add all the numbers together, and all the variables

2^(-1x)-(3x+10)=0

We get rid of parentheses

2^(-1x)-3x-10=0

We add all the numbers together, and all the variables

-3x+2^(-1x)-10=0

We move all terms containing x to the left, all other terms to the right

-3x+2^(-1x)=10

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